May 16, 2018 · Using ∏i=1r (ar + 1) ∏ i = 1 r (a r + 1) where a a is the magnitude of the power a prime factor is raised by and r r is the number of prime factors. I get 24 24 possible factors. Is there an easy …

Feb 12, 2020 · My question is: will the line for numbers with $3$ prime factors be overtaken by another line or do 'most numbers have $3$ prime factors'? It it is indeed that case that most numbers have …

Jun 26, 2012 · It's factors are 1, 5, 7, 25, 35, 49, 175, 245, 1225 1, 5, 7, 25, 35, 49, 175, 245, 1225 and the sum of factors are 1767 1767. A simple algorithm that is described to find the sum of the factors …

What I'm doing currently is that I use a prime sieve to find the primes $\leq \sqrt {n}$, then I loop through the list of primes (starting from $2$), checking divisibility --- if divisible, I write that prime to a list of …

Oct 20, 2015 · How do I express $108$ as the product of powers of its prime factors? I've got $2^2 \\times 3^3$ is this correct?

Public-key cryptography is based on the premise that large prime factors are hard to find. But lucky for you, you have a number with lots of easy small prime factors.

Jul 1, 2019 · What are the numbers that have at least four distinct prime factors up to $500$? The first number is $210$ and the four factors are($2,3,5,7$) next number is $330 \\ (2,3,5,11)$. what are the …

Mar 1, 2021 · Using common notation, ω(n) ω (n) is the number of distinct prime factors on n n. Similiarly, Ω(n) Ω (n) is the number of prime factors of n n, not necessarily distinct: 120 = 23 ⋅ 3 ⋅ 5 …

Get numbers that have only 2,3 and 5 as prime factors Ask Question Asked 13 years, 4 months ago Modified 4 years, 10 months ago

Mar 14, 2023 · For instance it is more common to speak about prime factors than about prime divisors; the two basically mean the same thing, but a given prime factor might be considered to occur …